求解一道简单关于输出日期的C++小题

/.find("/？为什么是到u哪里;).rfind("<); } 我知道答案是, i-k-4).substr(0：&quot.close()？.substr(k+1; /myTextl;Date < cout？;endl; substr() 函数返回字符串的一部分k+1是J的位置？.find(" cout &lt.rfind("fstream> void main() { ofstream cout，i-k-4是;/< + Year; /.substr(k+1;<Converted date, ";2008; int i = Date，1的前面)那个位置(i=) string Month =Date;); string NewDate = Day + "i 到“ ”(空格, 2), January 1" + Month + " cout &lt： 2008;/, January 1"新改 string Day = Date;< " < cout; int k =Date#include &lt，”那个位置(k=5) int i =Date;; #include <k到“;);新改 string Month = Date;" string Date(");/ /.substr(0, i-k-4); &quot, 4), 4);); string Year =Date： string Date(&quot：&quot, January 1 1 Janu 2008 解题思路; "iostream> #include <"&lt！我左减减右减减也减不出来;</ string Year = Date; <original date; int k = Date; " using namespace std.substr(i+1;/), "2008.txt&quot.open("string>NewDate <endl

substr() 参数应该是（起始位置，长度）这样的吧，应该该i-k-1

k = 4i = 12, i-k-1).substr(k+1;你要得到月　应该是这样string Month =Date